A milkman purchases the milk Rs- x per litre and sells it Rs- 2x per litre still he mixes 2 litres water with every 6 litres of pure milk- What is the profit percentage-

Question

Toppr Admin · Accepted Answer

Let the C-P of 1 liter pure milk be Rs 1 - then6 l milk cost - 6 rupees - Rs 6 only2 l water cost - 0 rupees8 liter mixture -x21D2- S-P - 8-xD7-2-16 ruppesprofit - - 16-x2212-66-xD7-100-10-xD7-1006-5-xD7-1003-166-66-

A milkman purchases the milk at Rs. $x$ per litre and sells it at Rs. $2 x$ per litre still he mixes $2$ litres water with every $6$ litres of pure milk. What is the profit percentage?

Let the C.P of 1 liter pure milk be Rs 1 , then
6 l milk cost _ 6 rupees = Rs 6 only
2 l water cost _ 0 rupees
8 liter mixture $\Rightarrow$ S.P = $8 \times 2 = 16$ ruppes
profit % = $\frac{16 - 6}{6} \times 100 = \frac{10 \times 100}{6} = \frac{5 \times 100}{3} = 166.66$ %

A milkman purchases the milk at Rs. x per litre and sells it at Rs. 2x per litre still he mixes 2 litres water with every 6 litres of pure milk. What is the profit percentage?

Let the C.P of 1 liter pure milk be Rs 1 , then6 l milk cost ___ 6 rupees = Rs 6 only2 l water cost ___ 0 rupees8 liter mixture ⇒ S.P = 8×2=16 ruppesprofit % = 16−66×100=10×1006=5×1003=166.66%

A milkman purchases the milk at Rs. $x$ per litre and sells it at Rs. $2 x$ per litre still he mixes $2$ litres water with every $6$ litres of pure milk. What is the profit percentage?

Let the C.P of 1 liter pure milk be Rs 1 , then
6 l milk cost _ 6 rupees = Rs 6 only
2 l water cost _ 0 rupees
8 liter mixture $\Rightarrow$ S.P = $8 \times 2 = 16$ ruppes
profit % = $\frac{16 - 6}{6} \times 100 = \frac{10 \times 100}{6} = \frac{5 \times 100}{3} = 166.66$ %