A mixture of 2 moles of CH4 & 34 gms of H2S was placed in an evacuated container, which was then heated to & maintained at 727∘C. When equilibrium was established in the gaseous reaction CH4+2H2S⇌CS2+4H2; the total pressure in the container was 0.92 atm & the partial pressure of hydrogen was 0.2 atm. What was the volume of the container?
298L
400L
330.18L
480L
A
298L
B
400L
C
330.18L
D
480L
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Solution
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CH4+2H2S→CS2+4H2 2 1 2-x 1-2x x 4x pH2=4xP/(3+2x);0.2(3+2x)=4x×0.92 x=0.1875. So volume of container is V=nRT/P=4×0.18×0.083×1000/0.2=298L.
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