A monatomic gas is suddenly compressed to $(1 / 8)$ th of its initial volume adiabatically. The ratio of its final pressure to the initial pressure is
(Given, the ratio of the specific heats of the given gas to be $5 / 3$ ).

Question

A monatomic gas is suddenly compressed to

(1 / 8)

th of its initial volume adiabatically. The ratio of its final pressure to the initial pressure is
(Given, the ratio of the specific heats of the given gas to be

5 / 3

).

Toppr Admin · Accepted Answer

It is given that CpCv-x3B3-53For an adiabatic process-P1V-x3B3-1-P2V-x3B3-2-x27F9-P2P1-V1V2-5-3-81-5-3-32

A monatomic gas is suddenly compressed to $(1 / 8)$ th of its initial volume adiabatically. The ratio of its final pressure to the initial pressure is
(Given, the ratio of the specific heats of the given gas to be $5 / 3$ ).
$40 / 3$
$24 / 5$
$32$
$8$

It is given that $\frac{C_{p}}{C_{v}} = γ = \frac{5}{3}$
For an adiabatic process,
$P_{1} V_{1}^{γ} = P_{2} V_{2}^{γ}$
$⟹ \frac{P_{2}}{P_{1}} = (\frac{V_{1}}{V_{2}})^{5 / 3}$
$= (\frac{8}{1})^{5 / 3} = 32$

A monatomic gas is suddenly compressed to (1/8)th of its initial volume adiabatically. The ratio of its final pressure to the initial pressure is(Given, the ratio of the specific heats of the given gas to be 5/3).40/324/5328

It is given that CpCv=γ=53For an adiabatic process,P1Vγ1=P2Vγ2⟹P2P1=(V1V2)5/3=(81)5/3=32

A monatomic gas is suddenly compressed to $(1 / 8)$ th of its initial volume adiabatically. The ratio of its final pressure to the initial pressure is
(Given, the ratio of the specific heats of the given gas to be $5 / 3$ ).
$40 / 3$
$24 / 5$
$32$
$8$

It is given that $\frac{C_{p}}{C_{v}} = γ = \frac{5}{3}$
For an adiabatic process,
$P_{1} V_{1}^{γ} = P_{2} V_{2}^{γ}$
$⟹ \frac{P_{2}}{P_{1}} = (\frac{V_{1}}{V_{2}})^{5 / 3}$
$= (\frac{8}{1})^{5 / 3} = 32$