A monochromatic light is incident from air on a refracting surface of a prism of angle $$75^o$$ and refractive index $$n_0 = \sqrt{3}$$. The other refracting surface of the prism is coated by a thin film of material of refractive index n as shown in figure. The light suffers total internal reflection at the coated prism surface for an incidence angle of $$\theta \le 60^o$$. The value of $$n^2$$ is ____ .
Correct option is A. 1.5
For T.I.R at coating
$$\sin c = \dfrac{n}{\sqrt{3}}$$
Appling snell's law at first surface
$$\sin \theta = \sqrt{3} \sin (75 - c)$$
for limiting condition, at $$\theta = 60^o$$
$$\sin 60 = \sqrt{3} \sin (75 - c)$$
$$\dfrac{\sqrt{3}}{2} = \sqrt{3} \sin (75 - c)$$
$$\dfrac{1}{2} = \sin (75 - c) \Rightarrow \sin 30 = \sin (75 - c)$$
$$30 = 75 - c \Rightarrow c = 45^o$$
$$\dfrac{n}{\sqrt{3}} = \dfrac{1}{\sqrt{2}} \Rightarrow n^2 = \dfrac{3}{2} = 1.50$$
$$\sin c = \dfrac{n}{\sqrt{3}}$$
Appling snell's law at first surface
$$\sin \theta = \sqrt{3} \sin (75 - c)$$
for limiting condition, at $$\theta = 60^o$$
$$\sin 60 = \sqrt{3} \sin (75 - c)$$
$$\dfrac{\sqrt{3}}{2} = \sqrt{3} \sin (75 - c)$$
$$\dfrac{1}{2} = \sin (75 - c) \Rightarrow \sin 30 = \sin (75 - c)$$
$$30 = 75 - c \Rightarrow c = 45^o$$
$$\dfrac{n}{\sqrt{3}} = \dfrac{1}{\sqrt{2}} \Rightarrow n^2 = \dfrac{3}{2} = 1.50$$
A monochromatic light is incident from air on a refracting surface of a prism of angle 75o and refractive index n0=√3. The other refracting surface of the prism is coated by a thin film of material of refractive index n as shown in figure. The light suffers total internal reflection at the coated prism surface for an incidence angle of θ≤60o. The value of n2 is
A ray of light on a prism having one silvered surface, at an incident angle of 45∘ as shown in figure. After refraction and reflection it retraces the path, then the refractive index of prism material is (prism angle is 30∘)