A motorcyclist drives from A to B with a uniform speed of $30 k m h^{- 1}$ and returns with a speed of $20 k m h^{- 1}$ . Find the average speed.

Question

A motorcyclist drives from A to B with a uniform speed of 30 km h-1- and returns with a speed of 20 km h-1- Find the average speed-25km h-1-24km h-1-12 km h-1-37km h-1-

Toppr Admin · Accepted Answer

Let the length of the line segment AB be x-xA0-mThe time taken is given as t-distance covered-speedTotal time - t1-t2-x30-x20-5x60-xA0-hAverage speed - Total distance-Total time - 2x5x-60-24-xA0-km-h

A motorcyclist drives from A to B with a uniform speed of $30 k m h^{- 1}$ and returns with a speed of $20 k m h^{- 1}$ . Find the average speed.
$25 k m h^{- 1}$
$24 k m h^{- 1}$
$12 k m h^{- 1}$
$37 k m h^{- 1}$

Let the length of the line segment AB be $x m$

The time taken is given as t=distance covered/speed
Total time = $t_{1} + t_{2} = \frac{x}{30} + \frac{x}{20} = \frac{5 x}{60} h$
Average speed = Total distance/Total time = $\frac{2 x}{5 x / 60} = 24 k m / h$

A motorcyclist drives from A to B with a uniform speed of 30 km h−1 and returns with a speed of 20 km h−1. Find the average speed.25kmh−124kmh−112kmh−137kmh−1

Let the length of the line segment AB be x mThe time taken is given as t=distance covered/speedTotal time = t1+t2=x30+x20=5x60 hAverage speed = Total distance/Total time = 2x5x/60=24 km/h

A motorcyclist drives from A to B with a uniform speed of $30 k m h^{- 1}$ and returns with a speed of $20 k m h^{- 1}$ . Find the average speed.
$25 k m h^{- 1}$
$24 k m h^{- 1}$
$12 k m h^{- 1}$
$37 k m h^{- 1}$

Let the length of the line segment AB be $x m$

The time taken is given as t=distance covered/speed
Total time = $t_{1} + t_{2} = \frac{x}{30} + \frac{x}{20} = \frac{5 x}{60} h$
Average speed = Total distance/Total time = $\frac{2 x}{5 x / 60} = 24 k m / h$