A motorcyclist wants to drive on the vertical surface of wooden 'well' of radius 5m, with a minimum speed of 5√5m/s. Find the minimum value of coefficient of friction between the tyres and the wall of the well. (Take g=10m/s2)
Frictional force =f=mg Centripetal Force = Contact force =N=mv²r
=mg(mv²r)
=(5×10)(5√5)²
=50125=0.4
Minimum coefficient of friction between the tyres and wall of the well must be 0.4.