A non conducting semicircular disc (as shown in figure) has a uniform surface charge density σ. The electric potential at the centre of the disc:-
σιn(b/a)2πε0(b−a)
σ(b−a)2ε0
σ(b−a)4ε0
σ(b−a)4πε0
A
σ(b−a)4ε0
B
σ(b−a)4πε0
C
σ(b−a)2ε0
D
σιn(b/a)2πε0(b−a)
Open in App
Solution
Verified by Toppr
Was this answer helpful?
0
Similar Questions
Q1
A non conducting semicircular disc (as shown in figure) has a uniform surface charge density σ. The electric potential at the centre of the disc:-
View Solution
Q2
Calculate the electric field at the centre of a non-conducting semicircular ring of linear charge density σ as shown in the figure.
View Solution
Q3
From a uniformly charged disc of radius R having surface charge density σ, a disc of radius R2 is Removed as shown. What is the electric potential at point P?
View Solution
Q4
A thin non-conducting disc of radius R is uniformly charged with surface charge density σ. If potential at any point on the circumference of disc be V and total electrostatic potential energy of the disc be U, then
View Solution
Q5
A conductor PQ as shown in figure is charged.σA,σB,σC and σD are surface charge densities of points A,B,C and D respectively