0
You visited us 0 times! Enjoying our articles? Unlock Full Access!
Question

A nuclear reactor generated power at 50% efficiency by fission of 92235 into an equal fragment of, 46Pd116 with the emission of two 7-rays of 5.2 MeV each and three neutrons. The average B.E. per particle of 235 and Pd116 is 7.2 MeV and 8.2 MeV respectively. The amount of 235 consumed per hour to produce 1600Mw power is
  1. 128 gm
  2. 1.4 kg
  3. 140.5 gm
  4. 281 gm

A
1.4 kg
B
281 gm
C
140.5 gm
D
128 gm
Solution
Verified by Toppr

Was this answer helpful?
9
Similar Questions
Q1
A nuclear reactor generated power at 50% efficiency by fission of 92235 into an equal fragment of, 46Pd116 with the emission of two 7-rays of 5.2 MeV each and three neutrons. The average B.E. per particle of 235 and Pd116 is 7.2 MeV and 8.2 MeV respectively. The amount of 235 consumed per hour to produce 1600Mw power is
View Solution
Q2
Assuming that about 200MeV of energy is released per fission of 92U235 nuclei, the mass of U235 consumed per day in a fission reactor of power 1MW will be approximately
View Solution
Q3
The energy released per fission of 92U235 is 200 Mev. The fission rate of 92U235 required to produce 2 watt power is
View Solution
Q4

If 200MeV energy is released per fission of U235 nuclei. Find the mass of U235 consumed per day in a reactor of power 1MW assuming its efficiency as 80%.


View Solution
Q5
In a nuclear reactor, 235U undergoes fission liberating 200MeV of energy. The reactor has a 10% efficiency and produces 1000MeV power. If the reactor is to function for 10 yrs then find the total mass of uranium required.
View Solution