A parallel plat capacitor is made of two circular plates separated by a distance of 5mm and with a dielectric of dielectric constant 2.2 between them. When the electric field in the dielectric is 3×104V/m, the charge density of the positive plate will be close to:
3×104C/m2
6×104C/m2
6×10−7C/m2
3×10−7C/m2
A
3×104C/m2
B
6×104C/m2
C
3×10−7C/m2
D
6×10−7C/m2
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Solution
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Answer is C. By formula of electric field between the plates of a capacitor E=σKε0 σ=EKε0=3×104×2.2×8.85×10−12 =6.6×8.85×10−8 =5.841×10−7 ≅6×10−7C/m2
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