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Question

A parallel plate air capacitor has capacity 'C', a distance of separation between plate is 'd' and potential difference 'V' is applied between the plates. Force of attraction between the plates of the parallel plate air capacitor is:

A
$$\dfrac{{{C^2}{V^2}}}{{{d^2}}}$$
B
$$\dfrac{{C{V^2}}}{{2d}}$$
C
$$\dfrac{{C{V^2}}}{{d}}$$
D
$$\dfrac{{{C^2}{V^2}}}{{2{d^2}}}$$
Solution
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Correct option is D.
$$\dfrac{{C{V^2}}}{{2d}}$$

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