Question

A parallel plate air capacitor is charged to a potential difference of V volts. After disconnecting the charging battery the distance between the plates of the capacitor is increased using an insulating handle. As a result the potential difference between the plates:

A

increases

B

decreases

C

does not change

D

becomes zero

Medium

Solution

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Correct option is A)

Capacitance ,
For a charged capacitor
As the distance between the plates of the capacitor is increased the capacitance decreases  
As capacitance decreases the potential difference between the plates

Solve any question of Electrostatic Potential and Capacitance with:-

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