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Question

A parallel plate capacitor has two square plates with equal and opposite charges. The surface charge densities on the plate are +σ and σ respectively. In the region between the plates the magnitude of electric field is:
  1. σ2ε0
  2. σε0
  3. 0
  4. none of these

A
σ2ε0
B
0
C
none of these
D
σε0
Solution
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The magnitude of the electric field due to a charged plate is given as:
E=σ2ε0

The charge density on the upper plate is positive whereas on the lower plate it is negative.

Therefore, the electric field in the region between the two plates is the difference of the two fields.
It is given as:
Enet=σ2ε0σ2ε0

Enet=σε0

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