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Standard XII
Physics
Idea behind a PPC
Question

A parallel plate capacitor is charged. If the plates are pulled apart
  1. The capacitance increases
  2. The potential difference increases
  3. The total charge increases
  4. The charge and potential difference remain the same

A
The potential difference increases
B
The charge and potential difference remain the same
C
The total charge increases
D
The capacitance increases
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Solution
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Capacitance of a parallel plate capacitor
C=ε0AdC=ε0Ad
A parallel plate capacitor is charged (battery is disconnected) then the plates are pulled apart, the capacitance decreases while the charge remains the same
∵Potentialdifference=ChargeCapacitance∵Potentialdifference=ChargeCapacitance
∴∴ potential difference increases

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