A parallel plate capacitor is connected from a cell and then isolated from it. Two dielectric slabs of dielectric constant $$K$$ and $$2K$$ are now introduced in the region between upper half and lower half of the plate (as shown in Figure). The electric field intensity in upper half of dielectric is $${E}_{1}$$ and lower half is $${E}_{2}$$ then
A
$${E}_{1} = {2E}_{2}$$
B
Electrostatic potential energy of upper half is less that of lower half
C
Induced charges on both slabs are same
D
Charge distribution on the plates remains same after insertion dielectric
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Solution
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Correct option is A. $${E}_{1} = {2E}_{2}$$
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