Question

# A parallel plate capacitor of capacitance $$20 \mu F$$ is being charged by a voltage source whose potential is changing at the rate of 3 V/s. The conduction current through the connecting wires, and the displacement current through the plates of the capacitor, would be, respectively.

A
zero, $$60 \mu A$$
B
$$60 \mu A , 60 \mu A$$
C
$$60 \mu A ,$$ zero
D
zero , zero
Solution
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#### Correct option is B. $$60 \mu A , 60 \mu A$$Capacitance of capacitor $$C = 20 \mu F$$$$= 20 \times 10^{-6} F$$Rate of change of potential is,$$\left(\dfrac{dV}{dt} \right) = 3 v/s$$$$\implies q = CV$$$$\implies \dfrac{dq}{dt} = C \dfrac{dV}{dt}$$$$i_c = 20 \times 10^{-6} \times 3$$$$= 60 \times 10^{-6} A$$$$= 60 \mu A$$As we know that $$i_d = i_C = 60 \mu A$$

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