A parallel plate capacitor of capacitance 20μF is being charged by a voltage source whose potential is changing at the rate of 3 V/s. The conduction current through the connecting wires, and the displacement current through the plates of the capacitor, would be, respectively.
A
zero, 60μA
B
60μA,60μA
C
60μA, zero
D
zero , zero
Medium
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Updated on : 2022-09-05
Solution
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Correct option is B)
Capacitance of capacitor C=20μF =20×10−6F Rate of change of potential is,(dtdV)=3v/s ⟹q=CV ⟹dtdq=CdtdV ic=20×10−6×3 =60×10−6A =60μA As we know that id=iC=60μA
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