Question

A parallel plate capacitor with air between the plates has a capacitance of 8 pF (1pF = F). What will be the capacitance if the distance between the plates is reduced by half, and the space between them is filled with a substance of dielectric constant 6?

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Solution

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Let the initial distance between the plates be
Let be the area of each plate.
Capacitance of the parallel plate capacitor is given by:
                                  


Let be the dielectric constant.
               
As the distance between plates is reduced to half, new distance is 
                                             

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