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$Step 1: Initial capacitance$

Let the initial distance between the plates be $d.$

Let $A$ be the area of each plate.

Capacitance of the parallel plate capacitor is given by:

$C_{i}=dA∈_{0} $ $....(1)$

$Step 2: Capacitance after inserting dielectric$

Let $k$ be the dielectric constant.

$C_{f}=d_{′}kA∈_{0} $

As the distance between plates is reduced to half, new distance is $d_{′}=2d $

$∴C_{f}=d2kA∈_{0} =2kC_{i}=2×6×8pF=96pF$

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