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Question

A parallel plate capacitor with air between the plates is charged to a potential difference of 500V and then insulated. A plastic plate is inserted between the plates filling the whole gap. The potential difference between the plates now becomes 75V. The dielectric constant of plastic is :
  1. 10/3
  2. 5
  3. 20/3
  4. 10

A
10
B
20/3
C
10/3
D
5
Solution
Verified by Toppr

If C be the air filled capacitance , dielectric filled capacitance becomes C=KC where K is the dielectric constant.
Initial charge , qi=CVi=500C and final charge qf=CVf=75KC
As the system is isolated so charge will be constant.
Thus, qi=qf
500C=75KCK=50075=20/3

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