0
You visited us 0 times! Enjoying our articles? Unlock Full Access!
Question

A parallel-plate air capacitor has a capacitance of 4μF what be its new capacitance if a slab of dielectric constant 5 is introduced filling the entire space between the two plates?

Solution
Verified by Toppr

The capacitance is given as,

C=εAd

4=εAd

The new capacitance is given as,

Cn=5εAd

Cn=5×4

Cn=20μF

Was this answer helpful?
1
Similar Questions
Q1
A parallel-plate air capacitor has a capacitance of 4μF what be its new capacitance if a slab of dielectric constant 5 is introduced filling the entire space between the two plates?
View Solution
Q2
A parallel-plate capacitor has the air as a medium between its plates and its capacitance is C. A slab of the dielectric constant K is introduced so as to fill the left half of space of the capacitor, as shown. What is the new capacitance of the capacitor?
199421_c89c3bb2208e4d14a4b87a5749d304f1.png
View Solution
Q3
A parallel plate air capacitor has a capacitance of 100 μF. The plates are at a distance d apart. If a slab of thickness t(td) and dielectric constant 5 is introduced between the parallel plates, then the capacitance will be
View Solution
Q4
A parallel plate capacitor with air as a dielectric has capacitance C. A slab of dielectric constant K, having same thickness as the separation between the plates is introduced so as to fill one-fourth of the capacitor as shown in the figure. The new capacitance will be:
740455_cbf515703ae84b7486848906071feee4.png
View Solution
Q5
The capacitance of parallel-plate capacitor is 4μF. If a dielectric material of dielectric constant 16 is placed between the plates then the new capacitance will be :
View Solution