A parallel-plate capacitor has circular plates of radius and separation. (a) Calculate the capacitance.(b) Find the charge for a potential difference of .



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(a) The capacitance of a parallel-plate capacitor is given by , where is the area of each plate and is the plate separation. Since the plates are circular, the plate area is , where R is the radius of a plate. Thus,

(b) The charge on the positive plate is given by   = , where V is the potential difference across the plates. Thus,

Solve any question of Electrostatic Potential and Capacitance with:-

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