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Question

A particle carrying a charge e enters perpendicularly into a uniform magnetic field of induction B with momentum p. Then, the radius of the circular path is
  1. Bep
  2. pBe
  3. Bep
  4. peB

A
Bep
B
peB
C
Bep
D
pBe
Solution
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qvB=mv2R
R=mvBe=PBe (Charge q=e)

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