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Standard XII
Physics
Time Period Independent of Amplitude
Question
A particle executing SHM has a maximum speed of
0.5
m
s
−
1
and maximum acceleration of
1
m
s
−
2
.
The angular frequency of oscillation is:
2
r
a
d
s
−
1
0.5
r
a
d
s
−
1
0.5
π
r
a
d
s
−
1
2
π
r
a
d
s
−
1
A
2
r
a
d
s
−
1
B
2
π
r
a
d
s
−
1
C
0.5
r
a
d
s
−
1
D
0.5
π
r
a
d
s
−
1
Open in App
Solution
Verified by Toppr
Maximum velocity,
V
m
a
x
=
A
w
Maximum acceleration,
a
m
a
x
=
A
w
2
⟹
Angular frequency,
w
=
a
m
a
x
V
m
a
x
=
1
0.5
=
2
r
a
d
/
s
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Q1
A particle executing SHM has a maximum speed of
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and maximum acceleration of
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s
−
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.
The angular frequency of oscillation is:
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Q2
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