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Standard XII
Physics
Question

A particle executing SHM has amplitude of 4 cm., and its acceleration at a distance of 1 cm from the mean position is 3 cms−2. Its velocity be when it is at a distance of 2 cm from its mean position is
  1. 2cm/s
  2. 3cm/s
  3. 4cm/s
  4. 6cm/s

A
3cm/s
B
2cm/s
C
4cm/s
D
6cm/s
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Solution
Verified by Toppr

a=−ω2x
ω2=3;ω=√3radsec
v=ω√A2−x2
=√3×√16−4
=√3×√12=6cm/s

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