A particle executing S-H-M- has an amplitude of 6 cm- Its acceleration a distance of 2 cm from the mean position is 8 cm- s-2- - The maximum speed of particle is8 cm-s12 cm-s16 cm-s24 cm-s

Question

Toppr Admin · Accepted Answer

A-x2212-x3C9-2x-x3C9-2-4-x3C9-2radsecvmax-x3C9-A-12cms

A particle executing S.H.M. has an amplitude of $6 c m$ . Its acceleration at a distance of $2 c m$ from the mean position is $8 c m / s^{2}$ . The maximum speed of particle is

$8 c m / s$
$12 c m / s$
$16 c m / s$
$24 c m / s$

$a = - ω^{2} x$
$ω^{2} = 4; ω = 2 \frac{r a d}{s e c}$
$v_{m a x} = ω A = 12 \frac{c m}{s}$

A particle executing S.H.M. has an amplitude of 6cm. Its acceleration at a distance of 2cm from the mean position is 8cm/s2. The maximum speed of particle is8cm/s12cm/s16cm/s24cm/s

a=−ω2xω2=4;ω=2radsecvmax=ωA=12cms

A particle executing S.H.M. has an amplitude of $6 c m$ . Its acceleration at a distance of $2 c m$ from the mean position is $8 c m / s^{2}$ . The maximum speed of particle is

$8 c m / s$
$12 c m / s$
$16 c m / s$
$24 c m / s$

$a = - ω^{2} x$
$ω^{2} = 4; ω = 2 \frac{r a d}{s e c}$
$v_{m a x} = ω A = 12 \frac{c m}{s}$