A particle executing S.H.M. has an amplitude of 6cm. Its acceleration at a distance of 2cm from the mean position is 8cm/s2. The maximum speed of particle is

8cm/s

12cm/s

16cm/s

24cm/s

A

8cm/s

B

12cm/s

C

24cm/s

D

16cm/s

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Solution

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a=−ω2x ω2=4;ω=2radsec vmax=ωA=12cms

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