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>>Simple Harmonic Motion
>> $A particle executing simple harmonic mot$

Question

A particle executing simple harmonic motion of amplitude 5 cm has maximum speed of 31.4 cm/s. The frequency of its oscillation is :

A

1Hz

B

3Hz

C

2Hz

D

4Hz

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Updated on : 2022-09-05

Solution

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Correct option is A)

$V_{m a x} = a ω \Rightarrow f = \frac{ω}{2 π} = \frac{V _{m a x}}{2 π a} = \frac{3 1 . 4}{2 π \times 5} = \frac{3 1 . 4}{1 0 π} = 1 H z$

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