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Question

A particle executing simple harmonic motion of amplitude 5 cm has maximum speed of 31.4 cm/s. The frequency of its oscillation is :
  1. 3Hz
  2. 1Hz
  3. 4Hz
  4. 2Hz

A
1Hz
B
2Hz
C
4Hz
D
3Hz
Solution
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Vmax=aωf=ω2π=Vmax2πa=31.42π×5=31.410π=1Hz

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