A particle executing simple harmonic motion of amplitude 5 cm has maximum speed of 31.4 cm/s. The frequency of its oscillation is :
3Hz
1Hz
4Hz
2Hz
A
3Hz
B
1Hz
C
2Hz
D
4Hz
Open in App
Solution
Verified by Toppr
Vmax=aω⇒f=ω2π=Vmax2πa=31.42π×5=31.410π=1Hz
Was this answer helpful?
50
Similar Questions
Q1
A particle executing simple harmonic motion of amplitude 5 cm has maximum speed of 31.4 cm/s. The frequency of its oscillation is :
View Solution
Q2
A particle executing simple harmonic motion has an angular frequency of 6.28s−1 and amplitude of 10cm. The maximum speed of the particle is :
View Solution
Q3
A particle executing simple harmonic motion has an angular frequency of 6.28s−1 and amplitude of 10cm. The maximum acceleration of the particle is :
View Solution
Q4
A particle is executing simple harmonic motion between extreme positions given by (−1.−2.−3)cm and (1,2,1)cm. Its amplitude of oscillation is :
View Solution
Q5
A particle executing simple harmonic motion has an angular frequency of 6.28 s−1 and an amplitude of 10 cm, the speed when the displacement is 6 cm from the mean position is: