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Question

# A particle executing simple harmonic motion of amplitude 5 cm has maximum speed of 31.4 cm/s. The frequency of its oscillation is :3Hz1Hz4Hz2Hz

A
1Hz
B
2Hz
C
4Hz
D
3Hz
Solution
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#### Vmax=aω⇒f=ω2π=Vmax2πa=31.42π×5=31.410π=1Hz

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