A particle having a de Broglie wavelength of 1.0 $A^{0}$ is associated with a momentum of (given $h = 6.6 \times 10^{- 34}$ Js)
$6.6 \times 10^{- 26} k g$ m/s
$6.6 \times 10^{- 25} k g$ m/s
$6.6 \times 10^{- 24} k g$ m/s
$6.6 \times 10^{- 22} k g$ m/s

Question

A particle having a de Broglie wavelength of 1.0 $A^{0}$ is associated with a momentum of (given $h = 6.6 \times 10^{- 34}$ Js)
$6.6 \times 10^{- 26} k g$ m/s
$6.6 \times 10^{- 25} k g$ m/s
$6.6 \times 10^{- 24} k g$ m/s
$6.6 \times 10^{- 22} k g$ m/s

Toppr Admin · Accepted Answer

Momentum of a particle with given de Broglie wavalength-xA0-xA0- -xA0- -xA0- -xA0- -xA0- -xA0-h-x3BB-xA0- -xA0- -xA0- -xA0- -xA0- -xA0-6-6-xD7-10-x2212-341-xD7-10-x2212-10

A particle having a de Broglie wavelength of 1.0 A0 is associated with a momentum of (given h=6.6×10−34 Js)6.6×10−26kg m/s6.6×10−25kg m/s6.6×10−24kg m/s6.6×10−22kg m/s

Momentum of a particle with given de Broglie wavalength =hλ =6.6×10−341×10−10

A particle having a de Broglie wavelength of 1.0 $A^{0}$ is associated with a momentum of (given $h = 6.6 \times 10^{- 34}$ Js)
$6.6 \times 10^{- 26} k g$ m/s
$6.6 \times 10^{- 25} k g$ m/s
$6.6 \times 10^{- 24} k g$ m/s
$6.6 \times 10^{- 22} k g$ m/s

Momentum of a particle with given de Broglie wavalength
$= \frac{h}{λ}$

$= \frac{6.6 \times 10^{- 34}}{1 \times 10^{- 10}}$