Question

A particle is executing SHM with time period T. Starting from mean position, time taken by it to complete 5/8 oscillations, is 

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Updated on : 2022-09-05
Solution
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Total distance covered by the particle.

we divide this whole path in 8 intervals of .

so, 5/8 oscillations means, it has already completed oscillation(i.e. total dist. = 2A) and is half way to the other side i.e. A/2.

so, ,

substitute to get

now, total time taken = time to complete previous one half(2A) + time taken to complete

Solve any question of Oscillations with:-
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