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Updated on : 2022-09-05

Solution

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Total distance covered by the particle$=4A$.

we divide this whole path in 8 intervals of $A/2$.

so, 5/8 oscillations means, it has already completed$1/2$ oscillation(i.e. total dist. = 2A) and is half way to the other side i.e. A/2.

so,$A/2=Asinwt,w=2pi/T$ ,

substitute to get $t=T/12.$

now, total time taken = time to complete previous one half(2A) + time taken to complete$A/2=t/2+t/12=7T/12.$

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