A particle is projected from ground with velocity v at angle θ to horizontal. Average velocity of particle between point of projection and maximum height of projectile is-
v2√1+2cos2θ
v2√1+cos2θ
v2√1+3cos2θ
vcosθ
A
v2√1+cos2θ
B
v2√1+3cos2θ
C
v2√1+2cos2θ
D
vcosθ
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Solution
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Range of the projectile motion=R=2v2cosθsinθg
Maximum height attained by particle in the motion=h=u2y2g=u2sin2θ2g
Total time taken by the particle to reach the topmost point =t=2uyg=2usinθg
Average velocity of particle between two points is given as the displacement between the two points /time taken to reach that
point=√(R2)2+h2t=v2√1+3cos2θ
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