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Question

A particle moves along a straight line such that its displacement at any time t is given by s=t36t2+3t+4 metres. The velocity when the acceleration is zero is:-
  1. 3 m/s
  2. 12 m/s
  3. 42 m/s
  4. 9 m/s

A
3 m/s
B
12 m/s
C
42 m/s
D
9 m/s
Solution
Verified by Toppr

S=t362+3t+4
v=dsdt

So =3t212+3=v
again differentiate ,a=dvdt
6t12=0
t=2s
v=3(2)212×2+3=9ms1

Hence (D) is correct answer.

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