Question

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Updated on : 2022-09-05

Solution

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Correct option is D)

$=∫_{0}7−2x+3x_{2}dx$

$=[7x−22x_{2} +33x_{2} ]_{0}$

$=[7x−x_{2}+x_{3}]_{0}$

$=[7×5−5_{2}+5_{3}]−[0−0+0]$

$=[35−25+125]−0$

$=135J$

In this question, answer is 135 J not 70J

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