A particle moves along the x- axis from x=0 to x=5 m under the influence of a force given by F=7−2x+3x2.Work done in the process is
70
270
35
135
A
270
B
135
C
70
D
35
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Solution
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w=∫Fdx
=∫507−2x+3x2dx
=[7x−2x22+3x23]50
=[7x−x2+x3]50
=[7×5−52+53]−[0−0+0]
=[35−25+125]−0
=135J
In this question, answer is 135 J not 70J
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