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Question

A particle moves along the x-axis according to x=A[1+sinωt]. What distance does is travel in time interval from t=0 to t=2.5π/ω?
  1. 4 A
  2. 5 A
  3. 6 A
  4. 3 A

A
3 A
B
4 A
C
5 A
D
6 A
Solution
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t=2.5πω=2.5π(2π/T)=(2.5)(T2)
=5(T4)
Partieie starts from extreme position and in every T4 time it travels a distance A. So in time t=5(T/4) it will travel a distance 5A.

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