A particle moves along the x-direction with constant acceleration. The displacement, measured form a convenient position, is 2 m at time t = 0 and is zero when t = 10 s. If the velocity of the particle is momentary zero when t = 6s, determine the acceleration a the velocity v when t = 10s.

Question

A particle moves along the x-direction with constant acceleration. The displacement, measured form a convenient position, is 2 m at time t = 0 and is zero when t = 10 s. If the velocity of the particle is momentary zero when t = 6s, determine the acceleration a the velocity v when t = 10s.

Toppr Admin · Accepted Answer

Letinitialvelocitybeusoin6sitsvelocitybecomeszero-v-u-at-x21D2-0-u-6a-1-displacementtill10sis0-x2212-2-x2212-2m-x2212-2-ut-12at2-x21D2-x2212-2-u-xD7-10-12a-xD7-102-10u-50a-x21D2-u-5a-x2212-0-2-2-solving-1-and-2-a-0-2m-s2

A particle moves along the x-direction with constant acceleration. The displacement, measured form a convenient position, is 2 m at time t = 0 and is zero when t = 10 s. If the velocity of the particle is momentary zero when t = 6s, determine the acceleration a the velocity v when t = 10s.

Letinitialvelocitybeusoin6sitsvelocitybecomeszero.v=u+at⇒0=u+6a.....(1)displacementtill10sis0−2=−2m−2=ut+12at2⇒−2=u×10+12a×102=10u+50a⇒u+5a=−0.2....(2)solving(1)and(2)a=0.2m/s2