A particle moves such that its acceleration $^{'} a^{'}$ is given by $a = - b x$ where $x$ is the displacement from equilibrium position and $b$ is constant. The period of oscillation

Question

A particle moves such that its acceleration

^{'} a^{'}

is given by

a = - b x

where

x

is the displacement from equilibrium position and

b

is constant. The period of oscillation

Toppr Admin · Accepted Answer

A-x2212-x3C9-2x-x2212-bxThus- -x3C9-x221A-bThus- T-2-x3C0-x3C9-2-x3C0-x221A-b

A particle moves such that its acceleration $^{'} a^{'}$ is given by $a = - b x$ where $x$ is the displacement from equilibrium position and $b$ is constant. The period of oscillation
$2 π / \sqrt{b}$
$2 π / b$
$\sqrt{2 π / b}$
$2 \sqrt{π / b}$