A particle moves under the effect of a force $F = C x$ from $x = 0$ to $x = x_{1}$ . The work done in the process is (treat $C$ as a constant):
$\frac{C^{2}}{x_{1}^{2}}$
$C x_{1}^{2}$
$\frac{C x_{1}^{2}}{2}$
$\frac{C}{x_{1}^{2}}$

Question

A particle moves under the effect of a force F - C x from x - 0 to  x - x-1- The work done in the process is -treat C as a constant- dfrac -C-2-x-2-1-Cx-2-1- dfrac -Cx-2-1-2- dfrac -C-x-2-1-

Toppr Admin · Accepted Answer

Work Done -x222B-x10-x2192-F-d-x2192-x-xA0-x222B-x10Cx-dx-xA0-Cx212

A particle moves under the effect of a force F=Cx from x=0 to x=x1. The work done in the process is (treat C as a constant):C2x21Cx21Cx212Cx21

Work Done =∫x10→F.d→x =∫x10Cx.dx =Cx212

A particle moves under the effect of a force $F = C x$ from $x = 0$ to $x = x_{1}$ . The work done in the process is (treat $C$ as a constant):
$\frac{C^{2}}{x_{1}^{2}}$
$C x_{1}^{2}$
$\frac{C x_{1}^{2}}{2}$
$\frac{C}{x_{1}^{2}}$

Work Done $= \int_{0}^{x_{1}} \to F . d \to x$ $= \int_{0}^{x_{1}} C x . d x$ $= \frac{C x_{1}^{2}}{2}$