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- 4.0 m/s
- 5.0 m/s
- 5.5 m/s
- 4.8 m/s

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Solution

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The correct option is (**A) **4.0 m/s

Given,

The particle is covering half of the distance with 3 m/s

Other half distance in two equal time intervals with speed of 4.5 m/s and 7.5 m/s

Let the total distance traveled by the particle is S

So,

Time taken by the particle for the first half distance (t1)

t1=S23=S6

According to the question second half distance is traveled in two equal time time intervals

So,

Let time interval be t

We can write,

S2=4.5×t+7.5t⇒12t=S2

Or, t=S24

Now,

Total time t=t1+t+t=S6+S24+S24=S4

Total time t=t1+t+t=S6+S24+S24=S4

We know,

Averagespeed=TotaldistancetraveledTotaltimetaken

So,

Average = St=SS4=4m/s

Average = St=SS4=4m/s

Hence, the average speed is 4 m/s

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