A particle moving with velocity bar-V- is acted by three forces shown by the vector triangle PQR- The velocity of the particle will -

Question

Toppr Admin · Accepted Answer

Correct option is C- Remain constantAs forces are forming closed loop in same order-160-So- -vec-F-net- - 0-Rightarrow m -dfrac-d -vec-v-dt- - 0-Rightarrow -vec-v- - - constant

A particle moving with velocity $$bar{V}$$ is acted by three forces shown by the vector triangle PQR. The velocity of the particle will :

Correct option is C. Remain constant
As forces are forming closed loop in same order
So, $$\vec{F}_{net} = 0$$
$$\Rightarrow m \dfrac{d \vec{v}}{dt} = 0$$
$$\Rightarrow \vec{v} $$ = constant

A particle moving with velocity $$bar{V}$$ is acted by three forces shown by the vector triangle PQR. The velocity of the particle will :

Correct option is C. Remain constantAs forces are forming closed loop in same order So, $$\vec{F}_{net} = 0$$$$\Rightarrow m \dfrac{d \vec{v}}{dt} = 0$$$$\Rightarrow \vec{v} $$ = constant

Correct option is C. Remain constant
As forces are forming closed loop in same order
So, $$\vec{F}_{net} = 0$$
$$\Rightarrow m \dfrac{d \vec{v}}{dt} = 0$$
$$\Rightarrow \vec{v} $$ = constant