Question

# A particle of charge −16×10−18 coulomb moving with velocity 10 ms−1 along the x-axis enters a region where a magnetic field of induction B is along the y -axis, and an electric field of induction B is along the y-axis, and an electric field of magnitude 104V/m is along the negative z-axis. lf the charged particle continues moving along the x-axis, the magnitude of B is

A
103Wb/m2
B
105Wb/m2
C
1016Wb/m2
D
103Wb/m2
Solution
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#### Particle travels along x axis Hence Vy=Vz=0Electric feild is along the negative z axisEx=Ey=0Therefore net force on the particle →F=q(→E+V×→B)Resolve the motion along three coordinate axisax=Fxm=qm(Ex+VyBz−VxBy)ay=Fxm=qm(Ey+VzBx−Vxz)az=Fxm=qm(Ez+VxBy−VyBx)Since, Vy=Vz=0Ex=Ey=0Bx=Bz=0ax=ay=0az=qm(−Ez+VxBy)Again az=0 , as the particle transverse through the region undeflected Ez=VxByBy=EzVx=10410=103wb/m2

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