A particle of charge q and mass m moves in a circular orbit of radius r with angular speed ω. The ratio of the magnitude of its magnetic moment to that of its angular momentum depends on
ω and q
ω, q and m
q and m
ω and m
A
ω and q
B
q and m
C
ω, q and m
D
ω and m
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Solution
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The angular momentum L of the particle is given by L=mr2w where w=2πn. ∴ Frequency n=w2π; Further i=q×n=wq2π Magnetic Moment, M=iA=wq2π×πr2; ∴M=wqr22 So, ML=wqr22mr2w=q2m
Thus the required ratio depends upon both q and m.
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