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- rate of work done by the electric field at P is 34(mv2a)
- E=34(mv2qa)
- rate of work done by electric field at P is zero
- rate of work done by both the fields at Q is zero

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Solution

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Therefore, net work done from P to Q=32mv2

And all work is done by electric field therefore equating

qE(2a)=32mv2

⇒E=3mv24qa

⇒E=3mv24qa

Therefore, option A is correct.

Option B is wrong.

Using Dimensional Analysis of given option is of force not of power.

Option D is correct.

Because at Q, electric force is perpendicular to velocity vector.

Option B is wrong.

Using Dimensional Analysis of given option is of force not of power.

Option D is correct.

Because at Q, electric force is perpendicular to velocity vector.

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