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A particle of charge +q and mass m moving under the influence of a uniform electric field E^i and uniform magnetic field B^k follows a trajectory from P to Q as shown in figure. The velocities at P and Q are v^i and −2v^j. Among the following the correct statements is/are :

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Solution

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Therefore, net work done from P to Q=32mv2

And all work is done by electric field therefore equating

qE(2a)=32mv2

⇒E=3mv24qa

⇒E=3mv24qa

Therefore, option A is correct.

Option B is wrong.

Using Dimensional Analysis of given option is of force not of power.

Option D is correct.

Because at Q, electric force is perpendicular to velocity vector.

Option B is wrong.

Using Dimensional Analysis of given option is of force not of power.

Option D is correct.

Because at Q, electric force is perpendicular to velocity vector.

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