0
You visited us 0 times! Enjoying our articles? Unlock Full Access!
Question

A particle of charge q and mass m starts moving from the origin under the action of an electric field E=Eo^i and B=B0^i with a velocity v=v0^j. The speed of the particle will become 2v0 after a time
  1. t=2mv0qE
  2. t=3Bqmv0
  3. t=3mv0qE
  4. t=2Bqmv0

A
t=2mv0qE
B
t=2Bqmv0
C
t=3Bqmv0
D
t=3mv0qE
Solution
Verified by Toppr

E=E0^iB=B0^i

v=v0^jE

vB

Hence, the path of the particle is a helix with speed remaining constant for the circular path in the yz plane.

Magnitude of velocity of particle at any time t: v=v2x+v2y+v2z=(axt)2+v20 where v2y+v2z=v20

Given v=2v0

(2v0)2=v2x+v20

(vx)2=3(v0)2

vx=3v0

axt=3v0

(qEm)t=3v0

t=3v0mqE

Was this answer helpful?
26
Similar Questions
Q1
A particle of charge of q and mass m starts moving from the origin under the action of an electric field ¯¯¯¯E=E0^i and ¯¯¯¯B=B0^i with a velocity ¯¯¯v=v0^j. The speed of the particle will become 2v0 after a time

View Solution
Q2
A particle of charge q and mass m starts moving from the origin under the action of an electric field E=Eo^i and B=B0^i with a velocity v=v0^j. The speed of the particle will become 2v0 after a time
View Solution
Q3
A particle of charge q and mass m starts moving from the origin under the action of an electric field E=E0^i and B=B0^i with velocity v=v0^j. The speed of the particle will become 2v0 after time
View Solution
Q4
A particle of charge q and mass m starts moving from the origin under the action of an electric field E=E0iandB=B0i with a velocity V=V0i.The speed of the article will become52v0 after a time
View Solution