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# A particle of charge q=16×10−18 C moving with 10ms−1 along x−axis enter a magnetic field of induction B along the y−axis and an electric field 104 Vm−1 along negative z−direction. If the particle continues to move along x−axis then the strength of magnetic field is103 Wbm−2105 Wbm−210−3 Wbm−21016 Wbm−2

A
105 Wbm2
B
103 Wbm2
C
1016 Wbm2
D
103 Wbm2
Solution
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#### The particle moves along x−axis undeflected.Magnetic force: →Fmag=q(→v×→B)=q(10^i×→B)Electric force: →Fe=q→E=−q×104^k→Fmag+→Fe=0⇒q(10^i×→B)=q×104^k⇒→B=103^jWbm−2

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