0
You visited us 0 times! Enjoying our articles? Unlock Full Access!
Question

A particle of mass 12 kg is acted upon by a force f =(1002x2) when f is in newton and x is in metre. Calculate the wrok done by this force in moving the particle x=0 to x=10m. What will be the speed at x=10m if it starts from rest.

Solution
Verified by Toppr

Given ForceF=1002x2
And we know work done ΔW=Fdx where dx=displacement.
Now integrating the above equation from limits x=0 to x=10,we get,
W=100(1002x2)dx=|100x|100|23(x3|100=3000+20003=333.33J negative sign implies work is done by the system.
Also we know W=Fs where s=displacement=vt where v=velocity and t= time.
And Force F=ma=mvt given initial velocity u=0 m/s.
So work done W=mv2
333.3312=v
v=5.27m/s

Was this answer helpful?
0
Similar Questions
Q1
A particle of mass 12 kg is acted upon by a force f =(1002x2) when f is in newton and x is in metre. Calculate the wrok done by this force in moving the particle x=0 to x=10m. What will be the speed at x=10m if it starts from rest.
View Solution
Q2
A force F=0.5x=10 acts on a particle. Here F is in Newton and x is in metre. Calculate the work done during the displacement of the particle from x=0tox=2 metre.
View Solution
Q3
A force F=(2x+3x2) N acts on a particle in x direction, where F is in Newton and x is in metre. Find the work done by this force for the displacement from x=0 m to x=3 m.
View Solution
Q4

A force F=0.5x+10 acts on a particle in the x direction. Here F is in newton and x is in metre. Calculate the work done by the force during the displacement of the particle from x=0 to x=2 metre.


View Solution
Q5
A force F=(10+0.5x) acts on a particle in the x direction, where F is in newton and x is inmetre. Find the work done by this force during the displacement from x=0 to x=2.0 m
View Solution