A particle of mass 1kg is placed at a distance of 4m from the centre and on the axis of a uniform ring of mass 5kg and radius 3m. The work done to increase the distance of the particle from 4m to √3m is.
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Potential of a ring, V=−GMy
So initial, energy is −5G×15
Final energy is −5G×16
So the difference = Final − Initial =G6
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A particle of mass 1 kg is placed at a distance of 4 m from the centre and on the axis of a uniform ring of mass 5 kg and radius 3m. What is the work required to be done to increase the distance of the particle from 4m to 3√3m
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