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# A particle of mass 1kg is placed at a distance of 4m from the centre and on the axis of a uniform ring of mass 5kg and radius 3m. The work done to increase the distance of the particle from 4m to √3m is.G3JG4JG5JG6J

A
G3J
B
G4J
C
G5J
D
G6J
Solution
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#### Potential of a ring, V=−GMywhere, y=√x2+r2So initial, energy is −5G×15Final energy is −5G×16So the difference = Final − Initial =G6

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