Question

A particle of mass 1×1026 kg and charge 1.6×1019 C travelling with a velocity 1.28×106 ms1 along the positive Xaxis enters a region in which there is a uniform electric field E=102.4×103 kNC1 and magnetic field B=8×102^j Wbm2 , the direction of motion of the particles is :

A
along the positive X-axis.
B
along the negative X-axis.
C
at 45o to the positive X-axis.
D
at 135o to the positive X-axis.
Solution
Verified by Toppr

Force acting on the particle when it enters in the electric field & magnetic field is

Was this answer helpful?
0
Similar Questions
Q1

A particle of charge q and mass m moving with velocity v along the x - axis enters the region x>0 with uniform magnetic field B along positive z direction. The particle will penetrate in this region along x - axis up to a distance d equal to


View Solution
Q2

A particle of charge q and mass m moving with velocity v along the x - axis enters the region x>0 with uniform magnetic field B along positive z direction. The particle will penetrate in this region along x - axis up to a distance d equal to


View Solution
Q3

A particle of mass 1×1026 kg and charge 1.6×1019 C travelling with a velocity 1.28×106 ms1 along the positive X-axis enters a region in whch a uniform electric field E=(102.4×103 ^k) NC and magnetic field B=(8×102) ^j Wbm2 exists. The direction of motion of the particle is along

View Solution
Q4

A charged particle of charge 2 mC has a velocity equal to 2 m/s along the positive xaxis. If in the region, there exists a uniform magnetic field of 4 T, directed along the negative xaxis. The magnitude of magnetic force on the charged particle is equal to

​​​​​​​[0.77 Mark]

View Solution
Q5

A particle of mass 1×1026 kg and charge 1.6×1019 C travelling with a velocity 1.28×106 m/s along the positive X-axis enters a region in which a uniform electric field E and a uniform magnetic field of induction B are present. if E=102.4×103 ^k NC1 and B=8×102 ^j Wbm2, the direction of motion of the particles is

View Solution
Solve
Guides