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Question

A particle of mass 2 kg moves in simple harmonic motion and its potential energy U varies with position x as shown. The period of oscillation of the particle is:

219039

A

$\frac{2 π}{5}$ s

B

$\frac{2 2 π}{5}$ s

C

$\frac{2 π}{5}$ s

D

$\frac{4 π}{5}$ s

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Solution

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Correct option is D)

$\frac{1}{2} k A^{2} = 1.0$
$\frac{1}{2} k (0.4)^{2} = 1.0$
or $k = 12.5$ or $\frac{2 5}{2}$ N/m
$T = 2 π \frac{m}{k} = 2 π \frac{2}{\frac{2 5}{2}} = \frac{4 π}{5}$ s

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