A particle of mass 200 g executes linear simple harmonic motion with an amplitude 10 cm. When the particles at a point midway between the mean and the extreme position, its kinetic energy is $3 π^{2} \times 10^{- 3} J$ . Assuming the initial phase to be $\frac{2 π}{3}$ , the equation of motion of the particle will be :
y=10 sin $(2 π t + \frac{2 π}{3})$ cm
y=10 sin $(4 π t + \frac{2 π}{3})$ cm
y=10 cos $(2 π t + \frac{π}{6})$ cm
y=10 cos $(2 π t + \frac{π}{3})$ cm

Question

A particle of mass 200 g executes linear simple harmonic motion with an amplitude 10 cm. When the particles at a point midway between the mean and the extreme position, its kinetic energy is $3 π^{2} \times 10^{- 3} J$ . Assuming the initial phase to be $\frac{2 π}{3}$ , the equation of motion of the particle will be :
y=10 sin $(2 π t + \frac{2 π}{3})$ cm
y=10 sin $(4 π t + \frac{2 π}{3})$ cm
y=10 cos $(2 π t + \frac{π}{6})$ cm
y=10 cos $(2 π t + \frac{π}{3})$ cm

Toppr Admin · Accepted Answer