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>> $A particle of mass 200 g executes linear$

Question

A particle of mass 200 g executes linear simple harmonic motion with an amplitude 10 cm. When the particles at a point midway between the mean and the extreme position, its kinetic energy is $3 π^{2} \times 1 0^{- 3} J$ . Assuming the initial phase to be $\frac{2 π}{3}$ , the equation of motion of the particle will be :

A

y=10 sin $(2 π t + \frac{2 π}{3})$ cm

B

y=10 sin $(4 π t + \frac{2 π}{3})$ cm

C

y=10 cos $(2 π t + \frac{π}{6})$ cm

D

y=10 cos $(2 π t + \frac{π}{3})$ cm

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Updated on : 2022-09-05

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Correct option is A)

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