A particle of mass m is in a uni-directional potential field where the potential energy of a particle depends on the x-coordinate given by ϕx=ϕ0(1−cosax) & ′ϕ′0 and ′a′ are constants. Find the physical dimensions of ′a′ & ϕ0.
L−1,M1L2T−2
None of these
L−2,M1L3T−2
L−1,M0L2T−1
A
None of these
B
L−2,M1L3T−2
C
L−1,M0L2T−1
D
L−1,M1L2T−2
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Solution
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Since angle have no dimension
Therefore Dimensions of ax=M∘L∘T∘
⇒[a]=M∘L∘T∘[L]=L−1
Dimension of energy = [ϕ0]=[M1L2T−2]
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