A particle of mass M is situated the centre of spherical shell of mass and radius a- The magnitude of the gravitational potential a point situated -a-2- distance from the centre- will bedisplaystylefrac-2GM-a-displaystylefrac-4GM-a-displaystylefrac-3GM-a-displaystylefrac-GM-a-

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Toppr Admin · Accepted Answer

VP-Vsphere-Vpartical-GMa-GMa-2-3GMa

A particle of mass $M$ is situated at the centre of spherical shell of mass and radius $a$ . The magnitude of the gravitational potential at a point situated at $a / 2$ distance from the centre, will be
$\frac{2 G M}{a}$
$\frac{4 G M}{a}$
$\frac{3 G M}{a}$
$\frac{G M}{a}$

$V_{P} = V_{s p h e r e} + V_{p a r t i c a l}$
$= \frac{G M}{a} + \frac{G M}{a / 2} = \frac{3 G M}{a}$

A particle of mass M is situated at the centre of spherical shell of mass and radius a. The magnitude of the gravitational potential at a point situated at a/2 distance from the centre, will be2GMa4GMa3GMaGMa

VP=Vsphere+Vpartical=GMa+GMa/2=3GMa

A particle of mass $M$ is situated at the centre of spherical shell of mass and radius $a$ . The magnitude of the gravitational potential at a point situated at $a / 2$ distance from the centre, will be
$\frac{2 G M}{a}$
$\frac{4 G M}{a}$
$\frac{3 G M}{a}$
$\frac{G M}{a}$

$V_{P} = V_{s p h e r e} + V_{p a r t i c a l}$
$= \frac{G M}{a} + \frac{G M}{a / 2} = \frac{3 G M}{a}$