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Correct option is C)

$=∫(ydx−xdy)$ .........(1)

$∵x_{2}+y_{2}=a_{2}∴xdx+ydy=0$

$⇒W=∫(y(x−ydy )−xdy)=−∫xx_{2}+y_{2} dy$

$=−∫_{0}a_{2}−y_{2} a_{2} dy=−2πa_{2} $

It can be observed that the force is tangent to the curve at

each point and the magnitude is constant. The direction of

force is opposite to the direction of motion of the particle.

$∴$ work done = (force) (distance)

$=−x_{2}+y_{2} =2πa =−a×2πa =−2πa_{2} J$

$W=−2πa_{2} J$

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