Question

This question has multiple correct options

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Solution

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Correct options are C) and D)

Given,

$v_{2}=a−bx_{2}$

$∴v_{2}+bx_{2}=a$

$a/bx_{2} +av_{2} =1$

For a S.H.M:

$x=Asin(ωt+θ)$

$v=Aωcos(ωt+θ)$

$A_{2}x_{2} +A_{2}ω_{2}v_{2} =1$

Comparing both equations:

$a/b=A_{2}$

$a=A_{2}ω_{2}$

$∴b=ω_{2}$

$⇒ω=b $

$⇒f=2πω =2πb $

And, the motion is simple harmonic

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