A particle of mass M, moving with a velocity u makes a head on collision with a particle of m initially at rest so that the final velocities are along the same line. If the collision is elastic and Mm=k, then the final velocity of the second particle of mass m is :
2u1+k
2ku1+k
kMu22(1−k)
2u1−k
A
2u1+k
B
2ku1+k
C
2u1−k
D
kMu22(1−k)
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Solution
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initial momentum=Mu let V ad v be final velocities of M and m respectively. final momentum=MV+mv also the collision is elastic,e=1. u=v−V&Mu=MV+mvV=v−u v=2MuM+malso,M=kmv=2ku1+k
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